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24x^2-7x-16=0
a = 24; b = -7; c = -16;
Δ = b2-4ac
Δ = -72-4·24·(-16)
Δ = 1585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1585}}{2*24}=\frac{7-\sqrt{1585}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1585}}{2*24}=\frac{7+\sqrt{1585}}{48} $
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